判断无穷级数∑<sub>n=1</sub><sup>∞</sup>(n+1)/3<sup>n</sup>的敛散性.

题目类型: 问答题

题目内容

判断无穷级数∑n=1(n+1)/3n的敛散性.

正确答案

∵limn→∞un+1/un=limn→∞[(n+2)/3n+1]/ [(n+1)/3n]=limn→∞(n+2)/[3(n+1)]=1/3﹤1 ∴由达朗贝尔判别法得,原级数收敛.

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